Is it? Maybe, but what if you replace 5(7-5) by 5C, where C=(7-5)
Yes, I have a "math background" (through/including graduate school - "A"s) and I got "6".
Why? 60+5(7-5) is not the same as 60+5x(7-5). With the "x" missing before the (), the 5(7-5) is treated as a computational group -- as like you say 5C where C is (7-5).
My calculator agrees: By the calculator 60+5x(7-5) = 24 ; whereas, by the calculator 60+5(7-5) = 6.
But, at a minimum, the video shows that some folks see it differently -- so, one needs to be careful that they are not misunderstood.